Understanding Kirchoff's Law and Solving Circuit Problems

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SUMMARY

This discussion focuses on applying Kirchoff's Law to solve circuit problems, specifically calculating the current I3 in a circuit with a voltage source of 3.7V. The user initially misapplied the law, resulting in an incorrect calculation of -0.0183 instead of the expected 0.0187. Key insights include the importance of correctly identifying current directions during the KVL (Kirchoff's Voltage Law) walk around the circuit, which affects the sign of the voltage across resistors.

PREREQUISITES
  • Understanding of Kirchoff's Voltage Law (KVL)
  • Basic circuit analysis techniques
  • Familiarity with Ohm's Law
  • Knowledge of current direction conventions in circuits
NEXT STEPS
  • Study detailed examples of Kirchoff's Voltage Law applications
  • Learn about potential differences across resistors in series and parallel circuits
  • Explore circuit simulation tools like LTspice for practical applications
  • Review common mistakes in circuit analysis and how to avoid them
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone looking to improve their understanding of circuit analysis and Kirchoff's Laws.

Pochen Liu
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Homework Statement


upload_2018-11-5_12-29-56.png

How do I calculate the current I3?

Homework Equations


I know that I1 = I2 + I3
and that I2 = 0.4

The Attempt at a Solution


So we have a voltage source of 3.7V I would've thought that the equation for a clockwise circuit be
0.4R2 - 3.7 - 200I3 = 0 which gives me an answer of -0.0183 when it should be 0.0187

How am I using the law wrong and how can I prevent doing so in the future?
 

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Pochen Liu said:
So we have a voltage source of 3.7V I would've thought that the equation for a clockwise circuit be
0.4R2 - 3.7 - 200I3 = 0 which gives me an answer of -0.0183 when it should be 0.0187

How am I using the law wrong and how can I prevent doing so in the future?
You need to pay attention to the direction of the currents as you do your "KVL walk" around the circuit. For example, ##I_3## is flowing down through ##R_3##, so as you "walk over" ##R_3## going clockwise around the circuit you'll see a rise in potential.
 
gneill said:
You need to pay attention to the direction of the currents as you do your "KVL walk" around the circuit. For example, ##I_3## is flowing down through ##R_3##, so as you "walk over" ##R_3## going clockwise around the circuit you'll see a rise in potential.
Is this because if I go 'walk over' instead of using the voltage it will add? since it's coming from the other direction, therefore I need to change it's mathematical sign around right?
 
Pochen Liu said:
Is this because if I go 'walk over' instead of using the voltage it will add? since it's coming from the other direction, therefore I need to change it's mathematical sign around right?
Right, you need to account for the current directions. If you "walk" in the same direction of the current you'll see a potential drop across the resistor. If you "walk" against the direction of the current you'll see a potential rise.
 
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