Applying Newton's Laws; coefficient of kinetic force

In summary, to find the acceleration of a crate being pushed on a rough floor, you can use the equation a=g(sinθ-μkcosθ), where a is acceleration, g is the acceleration due to gravity, θ is the angle of the applied force, and μk is the coefficient of kinetic friction. Given a mass of 28 kg, an applied force of 322 N, and a coefficient of kinetic friction of 0.50, the acceleration of the crate can be calculated to be 10.8942038 m/s².
  • #1
pinkpony
1
0

Homework Statement


To move a large crate across a rough floor, you push on it with a force F at an angle of 21°, below the horizontal. Find the acceleration of the crate, given that the mass of the crate is m = 28 kg, the applied force is 322 N and the coefficient of kinetic friction between the crate and the floor is 0.50.



Homework Equations


a=g(sinθ-μkcosθ)

μk=-a/g


The Attempt at a Solution


a=9.81(0.836655639-(.5)(-0.54772926)
a=10.8942038m/s²
 
Last edited:
Physics news on Phys.org
  • #2
pinkpony said:

Homework Statement


To move a large crate across a rough floor, you push on it with a force F at an angle of 21°, below the horizontal. Find the acceleration of the crate, given that the mass of the crate is m = 28 kg, the applied force is 322 N and the coefficient of kinetic friction between the crate and the floor is 0.50.



Homework Equations





The Attempt at a Solution

Please list your relevant equations and attempt at a solution. Then someone will be glad to assist, once you show your work.
 

1. What is Newton's Second Law?

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. In other words, the greater the force applied to an object, the greater its acceleration will be. Similarly, the more massive an object is, the less it will accelerate for a given force.

2. How do you calculate the coefficient of kinetic friction?

The coefficient of kinetic friction is calculated by dividing the force of kinetic friction by the normal force. The force of kinetic friction can be determined by multiplying the coefficient of kinetic friction by the normal force.

3. How does the coefficient of kinetic friction affect an object's motion?

The coefficient of kinetic friction affects an object's motion by determining the amount of frictional force that opposes its motion. The higher the coefficient of kinetic friction, the greater the frictional force and the more difficult it is for the object to move. Conversely, a lower coefficient of kinetic friction means less frictional force and an easier time for the object to move.

4. How does Newton's Third Law apply to coefficient of kinetic friction?

Newton's Third Law states that for every action, there is an equal and opposite reaction. In the case of coefficient of kinetic friction, the force of friction acting on an object is equal and opposite to the force the object exerts on the surface it is moving on. This means that the coefficient of kinetic friction is determined by the properties of both the object and the surface it is moving on.

5. How can the coefficient of kinetic friction be changed?

The coefficient of kinetic friction can be changed by altering the properties of the object or the surface it is moving on. For example, the surface can be made smoother or rougher, or the object can be made heavier or lighter. Additionally, adding a lubricant to the surface can decrease the coefficient of kinetic friction, making it easier for the object to move.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
341
  • Introductory Physics Homework Help
Replies
3
Views
784
  • Introductory Physics Homework Help
Replies
13
Views
955
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
915
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
367
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
5K
Back
Top