MHB Applying Simpson's Rule with 7 Pieces: Solving the Int.

  • Thread starter Thread starter shamieh
  • Start date Start date
Click For Summary
Applying Simpson's Rule requires an even number of intervals, but with 7 data points, there are actually 6 intervals to consider. The user correctly identifies that they should use the values provided to estimate the integral from 0 to 2π. The calculation involves using the formula with alternating coefficients of 4 and 2 for the function values. The final estimate for the integral is approximately 6.774, confirming that the application of Simpson's Rule is valid in this case. Overall, the solution appears accurate and well-structured.
shamieh
Messages
538
Reaction score
0
When applying Simpson's rule, suppose I have to slice up my function into 7 pieces, which would be odd. Then how would I apply Simpson's rule to my problem? Doesn't the n have to be equal to some even number?

I'm a bit confused, here is the question.

Estimate $$\int ^{2\pi}_0 f(x) \, dx$$The following data was collected about a function f(x)
$$x|f(x)$$

$$0 | 1.000$$

$$\frac{\pi}{3} | 1.513$$

$$\frac{2\pi}{3} | 0.696$$

$$\pi | 1.000$$

$$\frac{4\pi}{3} | 1.107$$

$$\frac{5\pi}{3} | 0.937$$

$$2\pi | 1.000$$

Sorry if it looks sloppy, I don't remember how to draw tables on this forum, anyways, with that being said, They are giving me 7 values, so they want me to split it into 7 pieces correct? So they want $$\frac{\Delta x}{3} [ f(0) + 4(\pi/3) + 2( 2\pi/3) ... 2\pi]$$

By the way I am just guessing they want me to split it into 7 pieces. Maybe they just want 6? I'm just not too sure, I feel like the approximate area would need to include all values. Thanks in advance for your help
 
Physics news on Phys.org
You do have 7 data points, but only 6 intervals ($n=6$), so Simpson's Rule will work here with no problems. :D
 
Oh I see. I'll be back with my solution soon! :eek:
 
Can someone verify my solution? It looks reasonable, just want to make sure though.(Muscle)

So I ended up with $$[1.000 + 4(1.513) + 2(0.696) + 4(1.000) + 2(1.107) + 4(0.937) + 1.000]$$

Which turned out to be $$\approx 19.406$$

Then I did $$\frac{\pi}{9} \approx .34906585039$$

thus $$.34906585039 * 19.406 \approx 6.77397189284$$
 
Looks good to me! :D
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K