Applying the Mean Value Theorem

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SUMMARY

The discussion focuses on applying the Mean Value Theorem (MVT) to analyze the function f(x) over the interval -2.5 < x < 3.5, given that f(-2) = 1. Participants explore the implications of the derivative graph of f(x) to estimate values such as -2 < f(0) < -1 and f(3) > 4 + f(1). The conversation emphasizes the use of both quantitative and qualitative information from the graph to derive conclusions about the behavior of f(x) and its critical points, particularly around x = 0.5.

PREREQUISITES
  • Understanding of the Mean Value Theorem (MVT)
  • Familiarity with derivative graphs and their implications
  • Knowledge of the Intermediate Value Theorem (IVT)
  • Basic skills in analyzing function behavior through critical points
NEXT STEPS
  • Study the application of the Mean Value Theorem in various contexts
  • Learn how to analyze derivative graphs for function behavior
  • Explore the Intermediate Value Theorem and its applications
  • Practice problems involving critical points and their significance in calculus
USEFUL FOR

Students studying calculus, particularly those focusing on the Mean Value Theorem and function analysis, as well as educators seeking to enhance their teaching methods in these topics.

soe236
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Hey,
I know the basic definition of the MVT, but I'm having a lot of trouble applying it to this problem. I would greatly appreciate any kind of help or guidance.

A graph of the derivative of f(x) is displayed below. Information about the function f(x) is known only for -2.5 < x < 3.5. Also f(-2) = 1. Consider the graph carefully, and consider the information in both the numbers and the shapes of the graph (both "quantitative" and "qualitative" information).

the graph:
http://img148.imageshack.us/img148/5224/graphfx6.jpg

a) Explain why -2 < f(0) < -1. Look carefully at the graph and make estimates using the MVT. Explain the steps of your reasoning in detail.
b) Explain why f(3) > 4 +f(1). Again, use the MVT and explain your reasoning in detail.
c) How big and how small can f(1) - f(0) be?
d) Use the information in a), b), and c) to explain why f(3) must be positive.
e) Explain why f(x) = 0 must have a solution between 0 and 3. Use the IVT (intermediate value th.) and the
information obtained in previous parts of this problem.
 
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Starting from x = -2, how does f(x) behave, can you tell by looking at f'(x)?
 
EnumaElish said:
Starting from x = -2, how does f(x) behave, can you tell by looking at f'(x)?

well from x=-2 to about x=.5, f'(x) is negative which means f(x) is decreasing and f(x) is increasing on approx [0.5,3.5] ..do i do something with the first derivative test? I just don't know what the question is asking for or atleast what I have to find to answer it
 
and the critical point is at 0.5 if that's of any use?
 

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