Using the mean value theorem to prove the chain rule

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SUMMARY

The discussion focuses on using the Mean Value Theorem (MVT) to prove the chain rule for differentiable functions. The functions f and g are defined as C1 functions mapping open subsets of the real line. The chain rule is expressed as (g o f)'(x) = g'(f(x)) f'(x), which can be derived by applying the MVT to the composition of these functions. Participants emphasize the importance of understanding the relationship between the derivatives of the composed functions.

PREREQUISITES
  • Understanding of the Mean Value Theorem (MVT)
  • Knowledge of differentiable functions and C1 continuity
  • Familiarity with function composition
  • Basic calculus concepts, including derivatives
NEXT STEPS
  • Study the Mean Value Theorem in detail, focusing on its applications
  • Learn about the properties of C1 functions and their implications for differentiation
  • Explore the proof of the chain rule in calculus
  • Practice problems involving function composition and differentiation
USEFUL FOR

Students studying calculus, mathematics educators, and anyone looking to deepen their understanding of differentiation and the chain rule in calculus.

B3NR4Y
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Homework Statement


I and J are open subsets of the real line. The function f takes I to J, and the function g take J to R. The functions are in C1. Use the mean value theorem to prove the chain rule.

Homework Equations


(g o f)' (x) = g'(f (x)) f'(x)
MVT

The Attempt at a Solution


[/B]
I know that the open interval (an, x) is a subset of J.

Therefore I can apply the mean value theorem, but I have no clue where to go
 
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B3NR4Y said:

Homework Equations


(g o f)' (x) = g'(f (x)) f'(x)
This is slightly misleading. I prefer \frac{dg}{dx}=\frac{dg}{df}\cdot \frac{df}{dx}. That should give you a clue.
 

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