Approaching Jacobian Calculation for a Single Function with Multiple Variables

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SUMMARY

The discussion focuses on calculating the Jacobian for a single function with three variables, specifically the function (s^2 + sin(rt) - 3)/s. The Jacobian is represented as J = [∂f/∂s, ∂f/∂r, ∂f/∂t], where the values are substituted with (1, π, -1). Participants confirm that in this scenario, the Jacobian matrix is equivalent to the gradient of the function.

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Homework Statement
We must find the Jacobian of f(s,r,t)=s^2+sin(rt)-3. Compute J(f/s)(1, pi, -1).
Relevant Equations
f(s,r,t)=s^2+sin(rt)-3. Compute J(f/s)(1, pi, -1).
I'm used to calculating Jacobians with several functions, so my only question would be how do I approach solving this one with only one function but three variables?

I think our function becomes (s^2+sin(rt)-3)/since we are looking for J(f/s). So then would our Jacobian simply be J=[∂f/∂s ∂f/∂r ∂f/∂t] with finally our values substituted of (1, pi,-1)?
 
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Yes. The Jacobi matrix is simply the gradient in this case.
 
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fresh_42 said:
Yes. The Jacobi matrix is simply the gradient in this case.
Thank you, and sorry for the typo, I had meant "I think our function becomes (s^2+sin(rt)-3)/s since we are looking for J(f/s)."
 

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