- #1

CookieSalesman

- 103

- 5

^{2}).

I need to, with n=5 rectangles midpoint approximate it.

I've figured that I need something like i=1 and ending at 5 (right?), and the equation is just sin(x

^{2}) Δx

Delta x is 1/5.

Are those the correct steps?

I think that all I need to do...

is... uhh... Well, actually I'm not sure how to change x

^{2}. Should it be x

_{i}

^{2}?

If that's true, then I think all I need to do, to midpoint approxy is keep on incrementing i, and I think it naturally gives me a midpoint, right?