Approximation Using Taylor POlynomial

Click For Summary
To approximate e^-0.1 with an error less than 10^-3, the Taylor series for e^x is utilized, where x is replaced with -0.1. The series expansion is given by e^x = Σ(x^n/n!), starting from n=0. A Taylor polynomial is needed for the approximation, along with a remainder estimate to ensure the desired accuracy. The discussion emphasizes the importance of using the Taylor polynomial method rather than just the series for precise calculations. This approach effectively provides a means to achieve the required approximation.
e179285
Messages
24
Reaction score
0
Find an approximate value of the number e-0.1 with an error less than 10-3

ı know that ex = Ʃ(from zero to ınfinity) xn / n!=1+x/1!+x
2
/2!+...

ı don't know how to use e-0.1 in this question.Do ı write -0.1 instead of x in ex series?
 
Physics news on Phys.org
e179285 said:
ı know that ex = Ʃ(from zero to ınfinity) xn / n!=1+x/1!+x
2
/2!+...

ı don't know how to use e-0.1 in this question.Do ı write -0.1 instead of x in ex series?

yup! :biggrin:
 
Since you are asked to calculate to within a particular accuracy, what you need is not the Taylor series, but a Taylor polynomial plus remainder estimate.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
5
Views
2K
Replies
6
Views
3K
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
11
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K