Arc length of y = (e^x - e^-x)/2 from 0 to 2

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zcabral
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Homework Statement



Length of curve: y=1/2(ex-e-x) from 0 to 2


Homework Equations



s = ∫√[1+(dy/dx)^2] dx

The Attempt at a Solution



[sqrt(4+2e^(-x)+e^x)]*[-1+e^x]/[1+e^x].
= 3.323971
 
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Your notation is ambiguous. I'm guessing that your curve is,

[tex]y(x) = \frac{e^x-e^{-x}}{2}[/tex]

In which case it may be useful to note that,

[tex]\frac{e^x-e^{-x}}{2} = \sinh(x)[/tex]

Which (along with a hyperbolic identity) would greatly simplify your integrand.