- #1

The_Fritz

- 5

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## Homework Statement

Because gasoline is less dense than water, drums containing gasoline will float in water. Suppose a 260 L steel drum is completely full of gasoline.

What total volume of steel can be used in making the drum if the gasoline-filled drum is to float in fresh water?

## Homework Equations

P=[tex]\rho[/tex]*V*g

Archimedes' principle - the buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by that object.

## The Attempt at a Solution

[tex]\rho[/tex]_steel*V_steel*g+[tex]\rho[/tex]_gas*V*g=[tex]\rho[/tex]_water*V*g

Solve for V_steel: *gravity cancels*

V_steel= ([tex]\rho[/tex]_water*V)-([tex]\rho[/tex]_gas*V)/([tex]\rho[/tex]_steel)

plug in values:

density water = 1000 kg/m^3

density gas = 680 kg/m^3

density steel = 7800 kg/m^3

Volume of drum= 260 L = .26 m^3

Answer: 1.1 * 10^-2 (which was not the correct answer)