Archer and Sound Travelling Problem

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SUMMARY

The discussion centers on calculating the distance between an archer and a target based on the time delay of sound after an arrow is fired. The archer hears the "thwok" sound 3.0 seconds after firing the arrow, which travels at an average speed of 33 m/s, while the speed of sound is 340 m/s. By breaking the problem into two segments—arrow travel time and sound travel time—and setting their sum equal to 3 seconds, one can derive the distance to the target using the equation: d/33 + d/340 = 3.

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mathkid3
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An archer fires an arrow, which produces a muffled "thwok" sound after it hits a target. If the archer hears the "thwok" exactly 3.0 s after firing the arrow and the average speed of the arrow was 33 m/s, what was the distance sepa*rating the archer and the target? Use 340 m/ s for the speed of sound.I have the same problem with different values. If I could see an answer I could then see how to plug in on my other problem.
At least i hope too

(Smirk)

Thanks!
 
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For this problem, I would definitely draw a diagram, and label relevant quantities. Then I would probably break the problem up into two parts: arrow to target, and "thwok" sound to archer: treat those two events as one after the other.

Does that give you some ideas?
 
Pretty much the same thing- call the distance to the target, in meters, "d". At 33 m/s how long does it take the arrow to get to the target (in terms of d)? At 340 m/s, how long does it take the sound to get back to you (again in terms of d)? The sum of those two times must be 3 seconds. Solve that equation for d.
 

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