Archimedes Principle: B = δVg + T

[Kork]

Hi :)

When I have a container with water and put a piece of metal down in the water while it's hanging on the string, I know that there will be two forces pulling it upwords:

B = δVg
and the string force T

But the force pulling it down, is that the gravitation? Or is it a force that equals to the weight of the piece of metal?

 

[Doc Al]

But the force pulling it down, is that the gravitation? Or is it a force that equals to the weight of the piece of metal?

Yes and yes. Gravity pulls the metal downward. (That gravitational force is the weight of the object.)

 

[Kork]

I don't think I quite understand the buoyancy part.

If I tak a cointainer with water and take out an imaginaray area then the forces on the area would be the buoyancy and the gravitationa pulling down? Right?

 

[Kork]

Thank you very much!

 

[Doc Al]

I don't think I quite understand the buoyancy part.

If I tak a cointainer with water and take out an imaginaray area then the forces on the area would be the buoyancy and the gravitationa pulling down? Right?

Not sure what you mean by 'take out an imaginary area'. The forces on the submerged object will include the buoyant force and the weight of the object. (Maybe you can restate the question.)