Archimedes' principle -- Which box will sink first as we add coins....

Click For Summary
SUMMARY

The discussion centers on Archimedes' principle as it applies to five identical empty boxes floating in water, each with different dimensions. The boxes are filled with coins one by one to determine which can hold the most coins before sinking. The key conclusion is that the box that displaces the most water will hold the highest number of coins, emphasizing the importance of volume above the water level in relation to buoyancy. Box C (8 x 8 x 4 cm³) was initially chosen by one participant as the best option, but the conversation reveals the complexity of the problem when considering different box shapes and water displacement.

PREREQUISITES
  • Understanding of Archimedes' principle
  • Basic knowledge of buoyancy and water displacement
  • Familiarity with geometric volume calculations
  • Concept of thought experiments in physics
NEXT STEPS
  • Research the mathematical formulation of Archimedes' principle
  • Explore the relationship between box shape and buoyancy
  • Learn about water displacement and its applications in fluid mechanics
  • Investigate real-world examples of buoyancy in various materials
USEFUL FOR

Students of physics, educators teaching buoyancy concepts, and anyone interested in fluid mechanics and the practical applications of Archimedes' principle.

dkk
Messages
1
Reaction score
0
Member has been warned not to remove the template.
There are five empty box contains with the same weight. The upper side of each boxes are removed. These boxes are floating in a pool of water. Then to each box we put coins slowly one by one. Assuming the box does not tilt. Determine which of the following size of the box (p x l x t) can be filled with most coins before it sinks.

A.) 4 x 4 x 11 cm3
B.) 6 x 6 x 6 cm3
C.) 8 x 8 x 4 cm3
D.) 10 x 10 x 2 cm3
E.) 12 x 12 x 1 cm3

Don't have the answer, but I chose C as the answer. All boxes have the same weight. The box with the larger volume should be able to float better than the other boxes right?
 
Last edited by a moderator:
Physics news on Phys.org
Right.
 
I think it might be a little more complicated than that. Imagen that you add the same amount of coins to all the boxes at once and they all are sinking down. What do you think will happen?
 
andrevdh said:
I think it might be a little more complicated than that. Imagen that you add the same amount of coins to all the boxes at once and they all are sinking down. What do you think will happen?
First off you are changing the problem that says that the coins are added one at a time. However, I will imagine (as you asked me to do) that the same amount of coins are added to all boxes and that they all sink down. What I think will happen (as you said) is that they will all sink down. The point of the problem as stated is that the box that displaces the most water will hold the highest number of coins. Your point is ... ?
 
I was just engaging with the problem through a thought experiment and wondering what will be the difference between long slim boxes and fat low boxes as they sink while they hold the same amount of coins in order to get a better feeling for the problem, but you are right because the volume above the water level actually holds the answer to this problem.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 21 ·
Replies
21
Views
5K
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
10K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
1
Views
2K