Are Continuous Functions with Zero Integral a Subspace of C[a,b]?

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SUMMARY

The set of continuous functions \( f = f(x) \) on the interval \([a,b]\) such that \(\int_a^b f(x) \, dx = 0\) is indeed a subspace of \( C[a,b] \). This conclusion is based on the definition of a subspace, which requires closure under addition and scalar multiplication. Specifically, if \(\int_a^b f(x) \, dx = 0\) and \(\int_a^b g(x) \, dx = 0\), then it follows that \(\int_a^b (f(x) + g(x)) \, dx = 0\). Additionally, for any scalar \( k \), \(\int_a^b k f(x) \, dx = k \int_a^b f(x) \, dx = 0\), confirming the closure properties.

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gaborfk
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Yet another problem I need to get some starting help on:

Show that the set of continuous functions f=f(x) on [a,b] such that \int \limits_a^b f(x) dx=0 is a subspace of C[a,b]
Thank you
 
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I would start by checking the definition of subspace.
 
Definition of subspace means that the functions are closed under addition and scalar multiplication
 
gaborfk said:
Definition of subspace means that the functions are closed under addition and scalar multiplication

So can you show that that's true for the potential subspace in your example?
 
You mean that if \int \limits_a^b f(x) dx=0 and \int \limits_a^b g(x) dx=0, can I prove that \int \limits_a^b f(x)+g(x) dx=0? Also, if \int \limits_a^b f(x) dx=0 then k\int \limits_a^b f(x) dx=0?
 
Yeah, that's pretty much it. (Technically you also have to show that it's a subset, but in this case that's trivial.)
 
Thank you!

The "hard ones" are so easy sometimes...
 

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