MHB Are Corners Inflection Points on a Graph?

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Corners on a graph are not differentiable, which suggests they cannot be classified as inflection points since inflection points require a change in curvature where the second derivative exists. The discussion highlights that curvature is only defined where the second derivative is present, thus excluding corners from being inflection points. Additionally, the conversation touches on the nature of critical points at the endpoints of a function defined on a closed interval, where two-sided derivatives do not exist. Overall, the consensus is that corners signify a change in the rate but do not meet the criteria for inflection points. The relationship between differentiability and inflection points is crucial in understanding graph behavior.
karush
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in that at corners are not differentiable, does this mean that they also are not inflection points but at the same time a change in the rate.

https://www.physicsforums.com/attachments/517
on the graph above f(x) for [0,7] at x=4 and x=5 what is f' and f'' or does it not exist

thanks ahead(Dull)
 
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From what I have read, an inflection point is a point at which the curvature or concavity changes sign. Since curvature is only defined where the second derivative exists, I think you can rule out corners from being inflection points.

Great question, by the way! It reminds me of the question of whether, given a function defined on a closed interval, whether the endpoints are critical points (since the two-sided derivative does not exist there).
 

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