Are Cosets of Normal Subgroups Always Normal in Quotient Groups?

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SUMMARY

The discussion confirms that if H and K are normal subgroups of a group G, and K is a subgroup of H, then the quotient group H/K is indeed a normal subgroup of the quotient group G/K. The reasoning is based on the fact that elements of H/K, represented as cosets of K in H, are also cosets of K in G, thus satisfying the normality condition. The conclusion is supported by the relationship between the elements of H and G, specifically that for any g in G and h in H, the expression gK*hK*g^(-1)K simplifies to (ghg^{-1})K, confirming the normality of H/K in G/K.

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[SOLVED] normal subgroups

Homework Statement


My book states the following without any justification right before proving the Third Isomorphism Theorem: "If H and K are two normal subgroups of G and K \leq H, then H/K is a normal subgroup of G/K."
The elements of H/K are cosets of K in H. The elements of G/K are cosets of K in G. Therefore I think that statement is simply absurd. That is, the elements of H/K are not even contained in the quotient group G/K; therefore, they cannot possibly form a normal subgroup in G/K.

EDIT: wait, never mind, the cosets of K in H are also cosets of K in G; sorry
EDIT: and the reason H/K is normal in G/K is that gK*hK*g^(-1)K = (ghg^{-1})K = h' K since H is normal in G. Very EDIT: cool.

Homework Equations


The Attempt at a Solution

 
Last edited:
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The elements in H/K are, indeed, contained in G/K since H is contained in G: A general element in H/K is hK which is in G/K since h is in G.
 

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