Are Differential Distances Along Curved Surfaces Larger Than Fixed Distances?

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SUMMARY

The discussion centers on the relationship between differential distances along curved surfaces and fixed distances, specifically in the context of the Schrödinger equation and polar coordinates. The author demonstrates that by substituting differential elements, such as dx with dβ, one can effectively analyze distances along a hoop. The mathematical foundation relies on the identity involving polar coordinates, where the differential arc length is expressed as r²dθ² = dβ², confirming that differential distances on curves can be larger than those in fixed directions. This insight is crucial for understanding geometrical interpretations in quantum mechanics.

PREREQUISITES
  • Understanding of the Schrödinger equation
  • Familiarity with polar coordinates
  • Basic knowledge of differential calculus
  • Concept of arc length in geometry
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  • Explore the implications of differential geometry on physical systems
  • Investigate the proof of the relationship between chord lengths and arc lengths
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Physicists, mathematicians, and students studying quantum mechanics or differential geometry who seek to deepen their understanding of the relationship between curved surfaces and differential distances.

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I recently did a problem with some electron constraint to move on a hoop. It kind of surprised me that you just could take the old Schrödinger-equation with and let your
dx ->dβ, where β is the distance along the hoop.
Saying it in a less mathematical way, isn't a differential distance along something curved larger than a differential distance in a fixed direction? I do realize that a rigorous mathematician would shoot me for saying something like this, so how would he say it?
 
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In a problem like this the best suited thing to do is to pass to polar coordinates, so you can describe a loop more simply. Then in these coordinates with origin at the center of the loop which is at a fixed radius r, you have [itex]dx^2+dy^2=r^2d\theta^2=d\beta^2[/itex]. So it's simply the old good polar coordinates.
 
Remember this? ## \displaystyle \lim_{x \rightarrow 0 } \frac {\sin x} {x} = 1 ##.

It ensures that the length of a chord and the corresponding arc are about the same when they are small, let alone differential. It might be useful for you to follow the proof of the statement.
 

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