Are Faithful Representations the Most Interesting Group Representations?

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SUMMARY

The discussion centers on the concept of 'faithful representations' in group theory, defined as injective homomorphisms from a group G to the Automorphism group of an object S, represented mathematically as ##\phi : G \rightarrow Aut(S)##. It is established that the surjective restriction of a faithful representation results in an isomorphism, confirming the original group's structure is preserved. Participants debate whether faithful representations are less interesting than non-faithful ones, concluding that the value of a representation depends on its application. Additionally, 'group action' is clarified as a specific type of representation where S is a set.

PREREQUISITES
  • Understanding of group theory concepts, particularly 'faithful representations'
  • Familiarity with homomorphisms and isomorphisms in mathematics
  • Knowledge of Automorphism groups and their significance
  • Basic comprehension of group actions and their relation to representations
NEXT STEPS
  • Study the First Isomorphism Theorem and its implications in group theory
  • Explore the concept of Automorphism groups in detail
  • Learn about linear representations and their applications in various mathematical contexts
  • Investigate the differences between faithful and non-faithful representations in practical scenarios
USEFUL FOR

Students and researchers in mathematics, particularly those focusing on group theory, algebra, and representation theory. This discussion is beneficial for anyone seeking to deepen their understanding of group representations and their applications.

BruceW
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Hello everyone!
I've been learning some basic group theory (I'm new to the subject). And I had a (hopefully) fairly simple question. OK, so a 'faithful representation' is defined as an injective homomorphism from some group G to the Automorphism group of some object. Let's call the object S for now. (I'm speaking more generally than just linear representations). So, to use some mathematical notation, we have ##\phi : G \rightarrow Aut(S)## where ##\phi## is the homomorphism.

Now, we can define another representation ##\theta## to be the surjective restriction of ##\phi## (meaning ##\theta## is essentially the same as ##\phi##, but with the codomain restricted to the image of ##\phi##). Therefore, ##\theta## is an injective surjective homomorphism, meaning it is an isomorphism. So I guess now, my question is: does my logic make sense? To summarize: for every faithful representation, the surjective restriction of that representation is an isomorphism.

Also, as a less concrete follow-up question: does this mean that faithful representations are in a sense somewhat 'boring' ? The image of a faithful representation is isomorphic to the original group, so it seems like we haven't done much by using this representation of the group. It seems to me that the interesting and potentially useful representations are the non-faithful ones... Does that sound about right?

Finally, one last question (sorry so many questions). I've seen the term 'group action' used a few times and it looks like it means the same thing as a representation. Have I understood this correctly? Or are they different things?

Many thanks,
bruce
 
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BruceW said:
Hello everyone!
I've been learning some basic group theory (I'm new to the subject). And I had a (hopefully) fairly simple question. OK, so a 'faithful representation' is defined as an injective homomorphism from some group G to the Automorphism group of some object. Let's call the object S for now. (I'm speaking more generally than just linear representations). So, to use some mathematical notation, we have ##\phi : G \rightarrow Aut(S)## where ##\phi## is the homomorphism.

Now, we can define another representation ##\theta## to be the surjective restriction of ##\phi## (meaning ##\theta## is essentially the same as ##\phi##, but with the codomain restricted to the image of ##\phi##). Therefore, ##\theta## is an injective surjective homomorphism, meaning it is an isomorphism. So I guess now, my question is: does my logic make sense? To summarize: for every faithful representation, the surjective restriction of that representation is an isomorphism.

Yes, that is correct.

Also, as a less concrete follow-up question: does this mean that faithful representations are in a sense somewhat 'boring' ? The image of a faithful representation is isomorphic to the original group, so it seems like we haven't done much by using this representation of the group. It seems to me that the interesting and potentially useful representations are the non-faithful ones... Does that sound about right?

I don't see why that makes faithful representations boring. For example, if you can find a faithful linear representation of a group, then you can basically represent the group as matrices. I think this is very interesting because you describe your group in other terminology, while you lose no information. Furthermore, that other description (for example as permutations or matrices) could be interesting to compute things about your group.

But in any case, whether a representation is interesting or not depends on the application you have in mind.

Finally, one last question (sorry so many questions). I've seen the term 'group action' used a few times and it looks like it means the same thing as a representation. Have I understood this correctly? Or are they different things?

Usually, it indeed means a representation like you defined, but one where ##S## is a set. So a group is then represented as bijective functions on a set.
 
micromass said:
Yes, that is correct.
woah, super-fast reply. thanks micromass :)

micromass said:
I don't see why that makes faithful representations boring. For example, if you can find a faithful linear representation of a group, then you can basically represent the group as matrices. I think this is very interesting because you describe your group in other terminology, while you lose no information. Furthermore, that other description (for example as permutations or matrices) could be interesting to compute things about your group.
hmm I guess. But you could just choose certain matrices to be your group elements in the first place. Maybe using faithful representation is a nice way to acknowledge that the group of all invertible matrices is a 'natural' group, while your choice of a certain subgroup of these matrices (for example when you have finite cyclic group) is not going to be a nice natural choice (i.e. there are many choices which are different, but effectively do the same thing for our purposes).

micromass said:
But in any case, whether a representation is interesting or not depends on the application you have in mind.
yeah, that's true.

micromass said:
Usually, it indeed means a representation like you defined, but one where ##S## is a set. So a group is then represented as bijective functions on a set.
Ah, right. So a group action is a particular example of a representation. cool.
 
BruceW said:
Hello everyone!
I've been learning some basic group theory (I'm new to the subject). And I had a (hopefully) fairly simple question. OK, so a 'faithful representation' is defined as an injective homomorphism from some group G to the Automorphism group of some object. Let's call the object S for now. (I'm speaking more generally than just linear representations). So, to use some mathematical notation, we have ##\phi : G \rightarrow Aut(S)## where ##\phi## is the homomorphism.

Now, we can define another representation ##\theta## to be the surjective restriction of ##\phi## (meaning ##\theta## is essentially the same as ##\phi##, but with the codomain restricted to the image of ##\phi##). Therefore, ##\theta## is an injective surjective homomorphism, meaning it is an isomorphism. So I guess now, my question is: does my logic make sense? To summarize: for every faithful representation, the surjective restriction of that representation is an isomorphism.

Also, as a less concrete follow-up question: does this mean that faithful representations are in a sense somewhat 'boring' ? The image of a faithful representation is isomorphic to the original group, so it seems like we haven't done much by using this representation of the group. It seems to me that the interesting and potentially useful representations are the non-faithful ones... Does that sound about right?

Finally, one last question (sorry so many questions). I've seen the term 'group action' used a few times and it looks like it means the same thing as a representation. Have I understood this correctly? Or are they different things?

Many thanks,
bruce

For the 1st question:

Notice, by the first isomorphism theorem, if you have f: G-->H with trivial kernel {e}, then G/Ker(f)=G/{e}~ G ~ f(G). So you're right that this is an isomorphism into the image. Not a brilliant comment, but helps dot t's and cross-eyes.
 
Last edited:

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