Are pq and qp always 3-cycles?

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SUMMARY

The discussion centers on the permutations p = (3 4 1)(2 5) and q = (1 4 5 2), specifically examining their products pq and qp, which both yield 3-cycles. It is established that this outcome is not coincidental, as permutations that are conjugate share the same cycle structure. The inquiry highlights the relationship between fixed points in permutations and their products, concluding that fixed points in both permutations remain fixed in their products.

PREREQUISITES
  • Understanding of permutation notation and cycle structure
  • Familiarity with group theory concepts, particularly conjugacy
  • Knowledge of fixed points in permutations
  • Basic skills in mathematical proof techniques
NEXT STEPS
  • Study the properties of conjugate permutations in group theory
  • Learn how to prove cycle structures of permutation products
  • Explore fixed points and their implications in permutation groups
  • Investigate advanced topics in group theory, such as Sylow theorems
USEFUL FOR

Mathematics students, particularly those studying abstract algebra and group theory, as well as educators looking to deepen their understanding of permutations and their properties.

Brucezhou
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Homework Statement


In the text, the products pq and qp of the permutations (2 3 4) and (1 3 5) were seen to be different. However, both products turned out to be 3-cycles. Is this an accident?

Homework Equations


p=(3 4 1)(2 5)
q=(1 4 5 2)
where p and q are permutations

The Attempt at a Solution


Based on many examples I made, this is obviously not an accident. For example, if the product is equal to (1 3 4)(5 2)(6), then the other product will also in the form (a b c)(d f)(e). However, I cannot come up with a general way to prove the truth. I have tried to find any relationship between the number of fixed numbers(the number just moves to itself after permutation, such as "6" in the previous example) and the product, but it doesn't show any regality. The truth is that if a number is fixed in both permutations, then it must be fixed in the products.
 
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Brucezhou said:

Homework Statement


In the text, the products pq and qp of the permutations (2 3 4) and (1 3 5) were seen to be different. However, both products turned out to be 3-cycles. Is this an accident?

Homework Equations


p=(3 4 1)(2 5)
q=(1 4 5 2)
where p and q are permutations

The Attempt at a Solution


Based on many examples I made, this is obviously not an accident. For example, if the product is equal to (1 3 4)(5 2)(6), then the other product will also in the form (a b c)(d f)(e). However, I cannot come up with a general way to prove the truth. I have tried to find any relationship between the number of fixed numbers(the number just moves to itself after permutation, such as "6" in the previous example) and the product, but it doesn't show any regality. The truth is that if a number is fixed in both permutations, then it must be fixed in the products.

No, it's not an accident. Do you know any group theory? If two permutations are conjugate then they have the same cycle structure. Can you show pq and qp are conjugate?
 
Dick said:
No, it's not an accident. Do you know any group theory? If two permutation are conjugate then they have the same cycle structure. Can you show pq and qp are conjugate?
Group is in the next chapter. Thank you very much. I am learning that chapter.
 

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