Are the displacements the same?

  • Thread starter Thread starter shreddinglicks
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around the equivalence of two point loads and a distributed load in a structural analysis context. Participants explore the implications of assumptions made regarding the rigidity of beam elements and the resulting displacements in a mechanical system.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes they obtained the same answer for two problems and questions the possibility of equivalence between point loads and a distributed load.
  • Another participant challenges the assumption of a perfectly rigid middle section, suggesting that dropping this assumption would yield different results.
  • A participant seeks clarification on whether the assumption of rigidity implies that angular displacements at the ends of the center piece are considered zero.
  • One participant inquires about the specific beam elements used and the assumptions made regarding them.
  • A participant describes their use of a stiffness matrix for three beam elements, detailing their assumptions about fixed ends and zero angular displacement at the center element's nodes.

Areas of Agreement / Disagreement

Participants express differing views on the assumptions made regarding rigidity and displacement, indicating that multiple competing perspectives remain in the discussion.

Contextual Notes

Participants' assumptions about rigidity and the implications for displacement calculations are not fully resolved, and the discussion highlights potential dependencies on these assumptions.

shreddinglicks
Messages
225
Reaction score
7

Homework Statement


I have already completed both problems. I have the same answer for both of them. I was wondering if that is possible? Are the two point loads equivalent to the distributed load?

Homework Equations


Stiffness matrix

The Attempt at a Solution

 

Attachments

  • Captured.PNG
    Captured.PNG
    25.6 KB · Views: 522
Physics news on Phys.org
As far as I can see you assumed that the middle section is perfectly rigid. With this assumption you get the same result; applying a force uniformly over a perfectly rigid element is the same as applying half of the total force on each end. Drop that assumption and you'll see a difference.
 
I want to make sure I understand. When you say assuming the middle section is rigid. That means the assumption that I made that the angular displacements at the two ends of the center piece are equal to zero?
 
What are the three beam elements you used? What did you assume for these beam elements?

The setup is symmetric, sure.
 
I used the stiffness matrix on each element. The three elements range from 0<x<914, 914<x<2134, 2134<x<3048. I assumed since the ends were fixed that the displacements and rotations about those ends were not applicable which simplified my stiffness matrix. The nodes at my center element I assumed angular displacement was equal to zero. So my matrix looked like this.

[K][displacements] = [F]
[K] [v2;theta2;v3;theta3]=[ql/2;0;ql/2;0]

where
ql/2 = -1000
 

Similar threads

Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
3
Views
5K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
5
Views
2K