Are there any basic formulas for motion in kinematics?

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Homework Help Overview

The discussion revolves around basic formulas for motion in kinematics, specifically focusing on equations related to velocity, acceleration, and displacement. Participants are exploring the relationships between these variables in the context of a kinematics problem.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants share various kinematic equations and discuss their components, such as initial and final velocities, acceleration, and displacement. There is also a query about the equivalence of different variable notations used in different courses.

Discussion Status

Some participants have provided guidance on rearranging equations to solve for displacement, while others express uncertainty about their calculations. There is an ongoing exploration of the correct application of the formulas and the units involved.

Contextual Notes

Participants mention specific values for initial velocity, final velocity, acceleration, and displacement, indicating a practical problem context. There is also a reference to the loss of a formula sheet, which adds a layer of constraint to the discussion.

patrickking
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I have no idea if this is the right forum but I am doing the kinematics chapter in 2204 and I was wondering if anyone had the bassic forumlas for motion.
 
Last edited:
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Yea, try :

V = u+at

(V^2) = (u^2) + 2as

s = ut + 0.5a(t^2)

Where,

u = initial velocity
v = final velocity
s = distance (or more correctly displacement)
a = acceleration
t = time
 
In my corse we use V1 and V2, D is Displacement, Is this like V1= U, V2=V and D=S?
 
Last edited:
The given information to the simple problem I am trying to complete is V1=10, A=1, V2= 15 and D=?. I just lost my formula sheet and I am lost.
 
Yea its same thing as you've put there, and as for the first question you would use,

(v2^2) = (v1^2)+2ad

and rearrange for d
 
So to rearrange for D would you use D= (V1^2) + 2a over (V2^2)? I used that and ended up with 0.4 for my answer, I don't believe that's correct?
 
This is all in Meters per second also.
 
Nope that's wrong, rearrange it in these steps :

(v2^2) = (v1^2)+2ad

You want to clear everything off the right hand side to leave d on its own, so start by moving (v1^2) :

(v2^2) - (v1^2) =2ad

And now divide both sides by 2a, and so :

(v2^2) -(v1^2) = 2ad

((v2^2) -(v1^2))/2a = 2ad/2a

to get :

((v2^2) -(v1^2))/2a = d

As you can see the 2a on the right hand side cancels when you divide that side by 2a

And yea everythign is in SI units so that's meters per second, meters, seconds etc
 
OK I did that and came out with 125 m/s which I think looks like it may be correct. But I'm not sure.
 
  • #10
Not quite, you only divided by a, when its supposed to be divide by 2*a
And d is a distance so its measured in just m, m/s is for velocity
 

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