MHB Are these lines parallel, perpendicular, or neither?

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The discussion focuses on solving a quadratic equation and determining the relationship between two lines. The quadratic equation 2x^2 + 4x - 15 = 0 was incorrectly solved, with the correct solution being x = -1 ± √(34)/2. For the lines y = -4x + 3 and x - 4y = 4, it was confirmed that they are perpendicular, as the product of their slopes equals -1. The participant received clarification on both problems, affirming their understanding. The thread highlights the importance of verifying mathematical solutions and relationships between lines.
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Basically I don't know anyone in real life that can help me with this, so I need help checking to see if my answers are correct :)

PART A

3) Solve 2x^2 + 4x = 15 by using the quadratic formula.

x = -1 +/- 2sqr34

4) Determine whether the given pairs of lines are parallel, perpendicular, or neither.

a) y = -4x + 3 b) x - 4y = 4

My answer: Perpendicular
 
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Re: Please check my answers - 2

3.) Incorrect.

We have:

$$2x^2+4x-15=0$$

$$x=\frac{-4\pm\sqrt{(4)^2-4(2)(-15)}}{2(2)}=\frac{-4\pm\sqrt{136}}{4}=\frac{-4\pm2\sqrt{34}}{4}=\frac{-2\pm\sqrt{34}}{2}$$

We could choose to write this as:

$$x=-1\pm\sqrt{\frac{17}{2}}$$

4.)

a) Correct. The product of the slopes of the two lines is -1.
 
Re: Please check my answers - 2

Thank you ! :)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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