MHB Are these lines parallel, perpendicular, or neither?

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The discussion focuses on solving a quadratic equation and determining the relationship between two lines. The quadratic equation 2x^2 + 4x - 15 = 0 was incorrectly solved, with the correct solution being x = -1 ± √(34)/2. For the lines y = -4x + 3 and x - 4y = 4, it was confirmed that they are perpendicular, as the product of their slopes equals -1. The participant received clarification on both problems, affirming their understanding. The thread highlights the importance of verifying mathematical solutions and relationships between lines.
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Basically I don't know anyone in real life that can help me with this, so I need help checking to see if my answers are correct :)

PART A

3) Solve 2x^2 + 4x = 15 by using the quadratic formula.

x = -1 +/- 2sqr34

4) Determine whether the given pairs of lines are parallel, perpendicular, or neither.

a) y = -4x + 3 b) x - 4y = 4

My answer: Perpendicular
 
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Re: Please check my answers - 2

3.) Incorrect.

We have:

$$2x^2+4x-15=0$$

$$x=\frac{-4\pm\sqrt{(4)^2-4(2)(-15)}}{2(2)}=\frac{-4\pm\sqrt{136}}{4}=\frac{-4\pm2\sqrt{34}}{4}=\frac{-2\pm\sqrt{34}}{2}$$

We could choose to write this as:

$$x=-1\pm\sqrt{\frac{17}{2}}$$

4.)

a) Correct. The product of the slopes of the two lines is -1.
 
Re: Please check my answers - 2

Thank you ! :)