Are These Vectors Linearly Independent in R*R?

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Homework Help Overview

The discussion revolves around determining the linear independence of various sets of functions in the vector space R*R. The specific sets under consideration include polynomial functions and trigonometric functions.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the definition of linear independence and question the relevance of certain expressions, such as sin^3 being expressed as a product of sin and sin^2. There is also discussion on how to demonstrate linear dependence for the sets involving sin^2 and cos^2.

Discussion Status

The discussion is active, with participants providing insights into the definitions and implications of linear independence. Some guidance has been offered regarding how to approach the problem, particularly in using specific equations to test for linear dependence.

Contextual Notes

Participants are navigating the definitions and properties of linear independence within the context of functions, and there is an emphasis on finding solutions to specific equations involving the constants associated with the functions.

ak123456
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Homework Statement


determine whether the following are linear independent sets of vectors in the vector space R*R of all functions from R to R
a)fn:=1+t+...+t^n for n=1,...4
b) sin,sin^2 ,sin^3
c)1,sin^2,cos^2

Homework Equations





The Attempt at a Solution


can i do like this for (b)(c)
sin^3=sin(sin^2)
sin^2+cos^2=1
so they are linearly dependent sets
 
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ak123456 said:
sin^3=sin(sin^2)
That doesn't look like a linear combination.
 
wywong said:
That doesn't look like a linear combination.

why? I think sin^3=(sin) * (sin^2) is right
 
ak123456 said:
why? I think sin^3=(sin) * (sin^2) is right
It's right but completely irrelevant.

For b, use the definition of linear independence to show that the equation
c1*sin(t) + c2*sin2(t) + c3*sin3(t) = 0 has exactly one solution for the constants c1, c2, and c3. (If there is more than one solution, the functions are linearly dependent.)

For c, the functions 1, sin2(t) and cos2(t) are linearly dependent, as you said. The first function, 1, is a linear combination of the other two.

Another way to look at this is that the equation
c1*1 + c2*sin2(t) + c3*cos2(t) = 0 has a solution where not all of the constants are zero. One such solution is c1 = -1, c2 = 1, c3 = 1. There are lots of solutions.
 
Mark44 said:
It's right but completely irrelevant.

For b, use the definition of linear independence to show that the equation
c1*sin(t) + c2*sin2(t) + c3*sin3(t) = 0 has exactly one solution for the constants c1, c2, and c3. (If there is more than one solution, the functions are linearly dependent.)

For c, the functions 1, sin2(t) and cos2(t) are linearly dependent, as you said. The first function, 1, is a linear combination of the other two.

Another way to look at this is that the equation
c1*1 + c2*sin2(t) + c3*cos2(t) = 0 has a solution where not all of the constants are zero. One such solution is c1 = -1, c2 = 1, c3 = 1. There are lots of solutions.

i see thanks a lot
 

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