Are Trig Identities Needed for This Derivative Problem?

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Homework Help Overview

The discussion revolves around a derivative problem involving trigonometric functions and identities. Participants are exploring whether trigonometric identities are necessary for solving the derivatives of the given functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the necessity of using trigonometric identities in conjunction with taking derivatives. Some express confidence in their derivative solutions, while others question the role of trig identities in the problem.

Discussion Status

There is a mix of agreement and differing opinions on the approach to the problem. Some participants assert that derivatives should be calculated directly, while others suggest that trig identities are essential for matching answers. Guidance has been offered regarding the use of identities to simplify results.

Contextual Notes

Participants are navigating the balance between direct derivative calculations and the application of trigonometric identities. There is a mention of specific functions and their derivatives, but the completeness of the problem setup is not fully detailed.

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Homework Statement





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Homework Equations


Trig identities or straightforward derivative?


The Attempt at a Solution


Is the answers

1. C
2. B
3. A
4. D

I tried taking the derivative of these, but a friend of mine here told me it deals with trig identities and isn't a derivative equation at all. Is he wrong ?

I am pretty sure these are the solutions but i want to double check ...
 
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Your friend is wrong. You hae to take the derivatives of the four given functions, and then match the derivatives you got with the answers shown by using trig identities. For 1, C is correct. For the rest, use trig identities to simplify the answers and compare your results with the derivatives you got for the given functions.
 
2. y= tan(x)
y'= sec^2(x)
Answer: D
trig identity used: 1+tan^2(x)= sec^2(x)

3. y=cos(tan(x))
y'= -sec^2(x)*sin(tan(x))
Answer: A

4.y=sin(x)tan(x)
y'=cos(x)*tan(x)+sec^2(x)*sin(x)
Answer: B

Is this correct? Thank you for the quick response by the way.
 
Thank you ! problem solved
 

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