Are x, y, and z elements of the normed linear space ℓ∞(ℝ)?

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SUMMARY

The discussion centers on the elements x, y, and z in the normed linear space ℓ∞(ℝ). It is established that x = (n-1)/n and y = 1/n are elements of ℓ∞(ℝ) as they are bounded above, while z = 2^n is not an element due to being unbounded. The calculations for x + y and 2^(1/2)y reveal that both results are not in ℓ∞(ℝ). The infinity norms are calculated, confirming that ||x||∞ = 1, ||y||∞ = 1, and ||x+y||∞ = 1, while ||2^(1/2)y||∞ is also determined to be 1.

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  • #31
bugatti79 said:
Is it L?

Would you be willing to change that to:

It is L!​

?

(Or else please clarify what is still puzzling you. :confused:)
 
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  • #32
I like Serena said:
Would you be willing to change that to:

It is L!​

?

(Or else please clarify what is still puzzling you. :confused:)


I don't really get "functional analysis"...but I will battle on anyway :-) Thanks
 
  • #33
So to go back to what you were trying to figure out much earlier in this thread, the infinity norm of x, where x = {1 - 1/n}, ||x|| = \lim_{n \to \infty}(1 - 1/n) = 1.
 

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