Area Calculation for Parametric Equation: x=t^3-5t, y=7t^2

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SUMMARY

The area enclosed by the parametric equations x=t^3-5t and y=7t^2 can be calculated using the integral ∫ (7t^2)(3t^2-5) dt. The bounds for the integral are determined by the values of t where x=0, specifically t=-√5, t=0, and t=√5. To find the total area, it is necessary to compute two separate integrals: one for the interval where x>0 and another for x<0, as the areas will yield different signs and must be summed to obtain the final result.

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Homework Statement


Find the area of the region enclosed by the parametric equation
x=t^3-5t
y=7t^2


Homework Equations





The Attempt at a Solution


I know how you set it up [tex]\int (7t^2)(3t^2-5)dt[/tex], but how do you find the bounds. I tried finding t and got t= (+/-)[tex]\sqrt{y/7}[/tex] and you plug it into x but where do you go from there.
 
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What I understand by enclosed means for the value of t where x=0. So the values are [tex]x=-\sqrt{5} , 0 , \sqrt{5}[/tex] So I guess you have to find two integrals, for x>0 and for x<0 because one will get negative and the other positive and to add them.
 

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