A triangle has verticies A(-2,1,3), B(7,8,-4), and C(5,0,2). Determine the area of the triange ABC.
The correct answer is 35.9 square units.
Has to be done by using dot product and/or cross product.
Dot product: a(dot) b= |a||b|cos(theta)
Cross product: a x b= |a||b|sin(theta)
||- this is used to indicate magnitude
The Attempt at a Solution
I tried using this formula AB (dot) BC x AC, and I got 358 units squared, which is incorrect. I am trying to get to the correct answer mentioned above. What would be the formula that would give me the correct answer? Please reply as soon as possible