1. The problem statement, all variables and given/known data If the height of a triangle is five centimeters less than the length of its base and if the area of the triangle is 52 cm^2, find the base and the height. 2. Relevant equations N/A 3. The attempt at a solution height = h-5 base = h A=(bh)/2 52=(h(h-5)/2 52=(h^2-5h)/2 104=h^2-5h h^2-5h-104=0 (h-13)(h+8)=0 h=13 or h=-8 h=-8 is extraneous; therefore the base is 13 and the height is 8. This is Grade 9 review and I don't think my teacher would include a problem using the quadratic equation. Is there an easier solution to this problem?