How Is the Area of a Relativistically Contracted Football Field Calculated?

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SUMMARY

The area of a relativistically contracted football field, consisting of a square with side length 1 meter and semi-circular arcs, is calculated using the length contraction formula L = L0√(1 - v²/c²). With an observer moving at 0.8c, the contracted length of the square's sides (AB and CD) is determined to be 0.6 meters, transforming the square into a rectangle. The semi-circular arcs are perceived as semi-elliptic arcs due to relativistic effects. The discussion emphasizes the need for complete problem statements to accurately apply these principles.

PREREQUISITES
  • Understanding of special relativity and length contraction
  • Familiarity with the formula L = L0√(1 - v²/c²)
  • Basic knowledge of geometric transformations (circle to ellipse)
  • Concepts of integral calculus for generalizing area calculations
NEXT STEPS
  • Study the implications of length contraction in special relativity
  • Explore the geometric transformation of shapes under relativistic conditions
  • Learn about integral calculus applications in area calculations
  • Investigate the effects of relativistic speeds on various geometric figures
USEFUL FOR

Students of physics, particularly those studying special relativity, mathematicians interested in geometric transformations, and educators preparing advanced physics problems.

Turhan
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Homework Statement



A football field is given in the following shape, where, ABCD is a square of side-length and AEB, CFD are semi-circular arcs. If an observer is moving with uniform velocity .along AB, what is the area of the football-field measured by the observer? ( is the velocity of light in free-space.)

EDIT: The side of the square is 1m and the speed of the observer is 0.8c.

Homework Equations



L=L0√1-v2/c2

The Attempt at a Solution


Okay so I know I have to use the length contraction equation. As the observer is moving along AB, the lengths of AB and CD will contract. The relativistic length is .6 meters. The square becomes a rectangle. What do I do with the semi circular regions?
P.S- Not any homework problem. Just a question from a previous olympiad.
 
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What happens to a circle when you squash it in one direction?
 
Simon Bridge said:
What happens to a circle when you squash it in one direction?
Ellipse. Thanks a lot captain.
 
I think the semi circular arcs will be viewed as semi-elliptic arcs from the moving observer.
 
The problem statement seems to be missing information regarding speeds and lengths. How did you find the relativistic length of 0.6 meters unless you know the observer speed and proper dimensions of the field? Can you provide a clear, complete statement of the problem as it was given to you?
 
gneill said:
The problem statement seems to be missing information regarding speeds and lengths. How did you find the relativistic length of 0.6 meters unless you know the observer speed and proper dimensions of the field? Can you provide a clear, complete statement of the problem as it was given to you?[/QU
The side of the square is 1m and the speed of the observer is 0.8c. Dont know ehre the info went and can't even edit it right now.
 
Turhan said:
The side of the square is 1m and the speed of the observer is 0.8c. Dont know ehre the info went and can't even edit it right now.
Thanks. There's a short window of time wherein one can edit their own posts, after which they're closed to alteration. I will take the information and add it for you.
 
Turhan said:
Ellipse. Thanks a lot captain.
There is a more general principle that may be of more use.

You know that shrinking a rectangle's width by a factor of k reduces its area by a factor of k. You know that shrinking a rectangle's length by a factor of k reduces its area by a factor of k. Can you generalize this to other shapes or other directions? If you know integral calculus, can you justify this generalization?

Edit: If you do not know integral calculus, what if you start by tiling the interior of an arbitrary planar shape with a bunch of small rectangles and squares of various sizes all lined up along the "shrink axis".
 

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