Area summation problem under a curve

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SUMMARY

The discussion centers on the area summation problem under a curve, specifically analyzing the expression $$\frac{\sqrt{1}+\sqrt{2}+...+\sqrt{n}}{n^{3/2}}$$. The presence of ##n^{3/2}## in the denominator is justified by the need to normalize the sum of square roots as the number of terms increases. The correct formulation involves using Riemann sums, where $$S_n=\sum_k f(c_k) \Delta x$$, with $$c_k=k \cdot \Delta x$$ and $$f(c_k)=\sqrt{c_k}$$, leading to the conclusion that substituting $$\Delta x=\frac{1}{n}$$ is essential for accurate evaluation.

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Karol
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Homework Statement


Snap2.jpg

Why, in:
$$\frac{\sqrt{1}+\sqrt{2}+...+\sqrt{n}}{n^{3/2}}$$
There is ##~n^{3/2}## in the denominator?

Homework Equations


Snap2.jpg


The Attempt at a Solution


it should be:
$$S_n=\sqrt{c_1}\Delta x+\sqrt{c_2}\Delta x+...=\Delta x\cdot \sqrt{\Delta x}+\Delta x\cdot \sqrt{2\Delta x}+...=\sqrt{\Delta x}\cdot \Delta x(\sqrt{1}+\sqrt{2}+...+\sqrt{n})$$
 
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Karol said:

Homework Statement


View attachment 135725
Why, in:
$$\frac{\sqrt{1}+\sqrt{2}+...+\sqrt{n}}{n^{3/2}}$$
There is ##~n^{3/2}## in the denominator?

Homework Equations


View attachment 135842

The Attempt at a Solution


it should be:
$$S_n=\sqrt{c_1}\Delta x+\sqrt{c_2}\Delta x+...=\Delta x\cdot \sqrt{\Delta x}+\Delta x\cdot \sqrt{2\Delta x}+...=\sqrt{\Delta x}\cdot \Delta x(\sqrt{1}+\sqrt{2}+...+\sqrt{n})$$
It should be ##\sum_k f(c_k) \Delta x##. Now ##c_k=k \cdot \Delta x\, , \,f(c_k)=\sqrt{c_k}## and ## \Delta x=\frac{1}{n}##. You simply stopped too soon before substituting ## \Delta x=\frac{1}{n}##.
 
Thank you fresh_42
 

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