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Area under v vs t sinusoidal trace

  1. Jan 5, 2014 #1
    if I have a sinusoidal trace on an oscilloscope (v vs t) and I wanted to find the area under the wave form squared graph I could integrate the sqaured waveform with respect to t.

    but since i dont have the integration facility... is it fair to say that the area under the graph is proprtional to vrms^2 ?

    im confused to what vrms is? the average v^2 value (i know its Vpeak/2)

    thanks
     
  2. jcsd
  3. Jan 5, 2014 #2

    davenn

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    wiki has a pretty good article on rms

    basically its 0.707 of the peak value
    and from what I remember the rms power of an AC circuit ( average power) is the equivalent to the DC power
    ( did that make sense ?) :smile:

    Dave
     
    Last edited: Jan 5, 2014
  4. Jan 5, 2014 #3
    An AC voltage of 10 volts rms ( no matter whether it is sinusoidal or not ) means that this AC voltage will heat up a resistor as a DC voltage of 10 volts.

    Remember that the power transformed into heat is V^2 / R.

    in a sinusoidal wave.

    No, it is proportional to Vrms an also proportional to Vpeak ( because it is a sinuoidal wave ).
     
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