Arranging resistors to have a minimum equivalent

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Tanishq Nandan
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Homework Statement



The minimum resistance obtained by connecting 50 resistances of 0.25 ohm each is
A)50/4ohm B)4/50 ohm C)200 ohm D)1/200 ohm
2.Relevant equations
1.When resistances are connected in series,
▪R(equivalent)=summation of all individual resistances
2.When resistances are connected in parallel ,
▪1/(equivalent resistance) =1/(summation of reciprocals of individual resistances)

The Attempt at a Solution


Minimum resistance is usually obtained when all resistances are connected in parallel (better than adding them all up).
So,it should be coming as 4/50 ohms,using formula 2,but the answer is given as D,1/200 ohms.

How do you arrange these resistors to have an equivalent resistance of 1/200 ohms??
 
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You have made a simple math error. Slow down and do it again. Show more intermediate steps if you want to know exactly which step is in error.
Tanishq Nandan said:
How do you arrange these resistors to have an equivalent resistance of 1/200 ohms??
You were correct when you said they should all be in parallel.
 
I got D as well. Check your calculations.
 
Yeah,got it,dumb me.Thanks,guys..