Finding the value of this load resistor

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SUMMARY

The discussion centers on calculating the value of a load resistor in a series circuit with a given electromotive force (emf) of 4000V. When connected to the load resistor, the voltage across it is 3000V, indicating that the internal resistance of the voltage supply accounts for 1000V. The current flowing through the circuit is calculated to be approximately 4.1666 x 10^-5 Amps, leading to the conclusion that the resistance of the load resistor is 72 Mega ohms.

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Bolter
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Homework Statement
Calculate the resistance of load resistor
Relevant Equations
V = IR
Question:

Screenshot 2020-02-14 at 09.05.33.png


I first knew that this would be a series circuit setup, there the current all around the circuit would be the same.

It's given that when it's a open circuit, p.d. across the output is 4000V hence the emf is therefore 4000V. When it gets connected to a load resistor, the voltage share is 3000V thus the voltage share on the internal resistance of the voltage supply must be 1000V

From this I can work out the current flowing through the circuit which gave me 4.1666... x10^-5 Amps

This should mean that 4.1666... x10^-5 amps is also passing through the load resistor, so the resistance of the load resistor is R = V/I or 72 Mega ohms

IMG-3860.JPG


Any help would be really appreciated. Thanks!
 
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No help possible, except to convince you you are doing OK...
 
BvU said:
No help possible, except to convince you you are doing OK...

Ok thanks, I’m sure I am doing it right. It’s just that sometimes I make silly mistakes that I don’t tend to see at all but others can. But I checked again just to be sure
 

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