Arrow hitting a target average force question

Click For Summary

Homework Help Overview

The problem involves an arrow with a mass of 8.0×10−2 kg that strikes a target at a speed of 25 m/s and penetrates 3.8 cm before coming to a stop. The questions raised pertain to calculating the average force exerted by the target on the arrow and vice versa.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the arrow, including gravity and drag forces. There is an attempt to apply kinematic equations to find acceleration based on the distance and speed. Some participants express uncertainty about how to proceed with the given information.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some have suggested using kinematic equations, while others are questioning how to connect these equations to the calculation of force. There is no explicit consensus yet on the approach to take.

Contextual Notes

Participants note the lack of clarity on how to apply the distance the arrow penetrates into the target and the implications of the forces involved in the scenario.

Capncanada
Messages
52
Reaction score
0

Homework Statement



A 8.0×10−2 kg arrow hits the target at 25 m/s and penetrates 3.8 cm before stopping.

Homework Equations



What average force did the target exert on the arrow?

What average force did the arrow exert on the target?

The Attempt at a Solution



I found the force the arrow's exerting before it hits the target I think...
(8*10^-2kg)*(9.8m/s^2)= 0.784N

I don't know where to go from here though.
 
Physics news on Phys.org
Sammy if you are reading this, correct me if I am wrong lol.

If it is already in the air and it is hitting something, it kinda means there is a drag force (resistance force) negating gravity.

So you are only concern with the horizontal force.

You have distance and speed, you can find the acceleration.
 
I only have the distance the arrow goes when it hits the target, I don't know how to apply it, I'm sorry.
 
[tex]v^2 = v_0 ^2 + 2a\Delta x[/tex]
 
And how do I use this to find the force?
 
F = ma
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
20
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K