A 0.075-kg arrow hits the target at 21 m/s and penetrates 3.8cm before stopping. (a) What average force did the target exert on the arrow? (b) What average force did the arrow exert on the target? (c) An identical arrow strikes the target at 42m/s. If the target exerts the same average force as before, what's the penetration depth?
Known: mass: .075kg velocity (?) 21m/s, displacement: 3.8cm
Here I am a little confused. (Or a lot confused)
Fnet=m x a
a=velocity final squared - velocity initial squared / 2(Δ)? Not sure if this equation applies
The Attempt at a Solution
I used the equation to figure out the acceleration since I have the mass. So here is where I am at:
a=0-(21m/s)2 / 2(.038m) = -5.8 x 10^3 m/s2
Then I used that to find Fnet=m x a = (.075kg)(-5.8 x 10^3m/s2)= -435N
I feel like I am on a completely wrong track and am not sure how to answer the question. Is the target applying a force of -435N?
Any help in the right direction is greatly appreciated, thank you for your time.