Artificial gravity meeting zero gravity

[dbell5]

Funny that these same calculations result in a counter-proof to the hollow-Earthers (Koreshian cosmogony):
If we did inhabit the inside surface of a hollow sphere the size of the Earth, the centripetal acceleration at the equator would be over 3G...

 

[brainstorm]

Funny that these same calculations result in a counter-proof to the hollow-Earthers (Koreshian cosmogony):
If we did inhabit the inside surface of a hollow sphere the size of the Earth, the centripetal acceleration at the equator would be over 3G...

So there is more force than just gravity holding the planet together?

 

[DaveC426913]

Funny that these same calculations result in a counter-proof to the hollow-Earthers (Koreshian cosmogony):
If we did inhabit the inside surface of a hollow sphere the size of the Earth, the centripetal acceleration at the equator would be over 3G...

How do you figure 3Gs?

If that were true, it would apply to the outer surface as much as the inner surface. What you are suggesting is that, standing on the outer surface of the Earth, I am experiencing a 3G pull away from the Earth!

 

[dbell5]

How do you figure 3Gs?

If that were true, it would apply to the outer surface as much as the inner surface. What you are suggesting is that, standing on the outer surface of the Earth, I am experiencing a 3G pull away from the Earth!

Huh! That would appear to be so! (Actually, 2G away, since the Earth's field is 1G inwards at the surface, vs. 0G inside a hollow shell.)

OK, here's how I got there:
a = v^2/r
Circumference of Earth is about 41,000 km, or 41e6 meters
Rotation is once in 86,400 seconds, for a tangential velocity of about 474 m/s.
Radius is about 6,500 km, which is where I went wrong - I divided by 6,500, not 6.5e6.
I got 34 m/s^2, should be 0.034 m/s^2

OK, so we're in no immediate danger of flying off into space!

Dave

 

[dbell5]

A corollary to the above that I never thought of is that, even if the Earth were a perfect, homogeneous sphere, and ignoring the bulky clothes, I'd weigh nearly 5 pounds more at the poles than I do here at 37°N!

 

[brainstorm]

A corollary to the above that I never thought of is that, even if the Earth were a perfect, homogeneous sphere, and ignoring the bulky clothes, I'd weigh nearly 5 pounds more at the poles than I do here at 37°N!

So that's why Santa is so heavy.