Artificial gravity meeting zero gravity

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SUMMARY

The discussion centers on the dynamics of artificial gravity (AG) in a rotating space station, specifically a design involving two hoops, one rotating and one stationary. Participants clarify that artificial gravity is not a true gravitational force but rather a result of inertia and tangential movement. An occupant will remain weightless until they make contact with a moving surface, which imparts tangential motion, allowing them to experience AG. The conversation also explores the implications of acceleration in different directions relative to the station's rotation and how this affects perceived weight and lift.

PREREQUISITES
  • Understanding of rotational dynamics and inertia
  • Familiarity with the concept of artificial gravity in space environments
  • Basic knowledge of aerodynamics and lift
  • Awareness of the physics of motion in low-gravity conditions
NEXT STEPS
  • Research the physics of inertia and its role in artificial gravity
  • Explore the design and mechanics of rotating space habitats
  • Learn about the effects of acceleration on perceived weight in a rotating system
  • Investigate the principles of lift and how they apply in low-gravity environments
USEFUL FOR

Aerospace engineers, physicists, and anyone interested in the mechanics of artificial gravity and the design of space habitats will benefit from this discussion.

  • #31
Funny that these same calculations result in a counter-proof to the hollow-Earthers (Koreshian cosmogony):
If we did inhabit the inside surface of a hollow sphere the size of the Earth, the centripetal acceleration at the equator would be over 3G...
 
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  • #32
dbell5 said:
Funny that these same calculations result in a counter-proof to the hollow-Earthers (Koreshian cosmogony):
If we did inhabit the inside surface of a hollow sphere the size of the Earth, the centripetal acceleration at the equator would be over 3G...

So there is more force than just gravity holding the planet together?
 
  • #33
dbell5 said:
Funny that these same calculations result in a counter-proof to the hollow-Earthers (Koreshian cosmogony):
If we did inhabit the inside surface of a hollow sphere the size of the Earth, the centripetal acceleration at the equator would be over 3G...

How do you figure 3Gs?

If that were true, it would apply to the outer surface as much as the inner surface. What you are suggesting is that, standing on the outer surface of the Earth, I am experiencing a 3G pull away from the Earth!
 
  • #34
DaveC426913 said:
How do you figure 3Gs?

If that were true, it would apply to the outer surface as much as the inner surface. What you are suggesting is that, standing on the outer surface of the Earth, I am experiencing a 3G pull away from the Earth!

Huh! That would appear to be so! (Actually, 2G away, since the Earth's field is 1G inwards at the surface, vs. 0G inside a hollow shell.)

OK, here's how I got there:
a = v^2/r
Circumference of Earth is about 41,000 km, or 41e6 meters
Rotation is once in 86,400 seconds, for a tangential velocity of about 474 m/s.
Radius is about 6,500 km, which is where I went wrong - I divided by 6,500, not 6.5e6.
I got 34 m/s^2, should be 0.034 m/s^2

OK, so we're in no immediate danger of flying off into space!

Dave
 
  • #35
A corollary to the above that I never thought of is that, even if the Earth were a perfect, homogeneous sphere, and ignoring the bulky clothes, I'd weigh nearly 5 pounds more at the poles than I do here at 37°N!
 
  • #36
dbell5 said:
A corollary to the above that I never thought of is that, even if the Earth were a perfect, homogeneous sphere, and ignoring the bulky clothes, I'd weigh nearly 5 pounds more at the poles than I do here at 37°N!

So that's why Santa is so heavy.
 

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