[ASK] Limit of Trigonometry Function

  • MHB
  • Thread starter Monoxdifly
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  • #1
Monoxdifly
MHB
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\(\displaystyle \lim_{x\to0}\frac{sin2x+sin6x+sin10x-sin18x}{3sinx-sin3x=}\)
A. 0
B. 45
C. 54
D. 192
E. 212

Either substituting or using L'Hopital gives \(\displaystyle \frac00\). Is there any way to simplify it and make the result a real number?
 

Answers and Replies

  • #2
I like Serena
Homework Helper
MHB
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We can repeat L'Hôpital until it's not $\frac 0 0$ any more.
 
  • #3
Monoxdifly
MHB
284
0
Ah, I see. It's in the third derivative and the answer is \(\displaystyle \frac{4,608}{24}\)= 192, right?
 
  • #4
I like Serena
Homework Helper
MHB
16,350
255
Ah, I see. It's in the third derivative and the answer is \(\displaystyle \frac{4,608}{24}\)= 192, right?
Yep. (Nod)
 

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