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\(\displaystyle \lim_{x\to0}\frac{sin2x+sin6x+sin10x-sin18x}{3sinx-sin3x=}\)
A. 0
B. 45
C. 54
D. 192
E. 212
Either substituting or using L'Hopital gives \(\displaystyle \frac00\). Is there any way to simplify it and make the result a real number?
A. 0
B. 45
C. 54
D. 192
E. 212
Either substituting or using L'Hopital gives \(\displaystyle \frac00\). Is there any way to simplify it and make the result a real number?