Asteroid Binding Energy: E=mv^2?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 2K views
Tris Fray Potter
Messages
13
Reaction score
0
If the binding energy in nuclear physics is e=mc^2, then would the binding energy of a larger object be:
e=mv^2
where v=the velocity of the asteroid?
 
Physics news on Phys.org
In the binding energy equation the m is the mass deficit ... does the concept of mass deficit apply to the asteroid?
In the asteroid equation, v is the speed of the asteroid; in the binding energy, the speed "c" appears in the same place... does that mean that the nucleus is moving at the speed of light?
In short: no. You cannot do physics by analogy.
 
  • Like
Likes   Reactions: Tris Fray Potter
Simon Bridge said:
In the binding energy equation the m is the mass deficit ... does the concept of mass deficit apply to the asteroid?
In the binding energy, the speed "c" appears ... does that mean that the nucleus is moving at the speed of light?
In short: no. You cannot do physics by analogy.
Okay. Thank-you. Do you know how I would be able to find the binding energy of the asteroid?
 
Tris Fray Potter said:
Okay. Thank-you. Do you know how I would be able to find the binding energy of the asteroid?

There are several types of binding energy. Which one are you looking for? Gravitational? Nuclear? Chemical?
 
  • Like
Likes   Reactions: Tris Fray Potter
Drakkith said:
There are several types of binding energy. Which one are you looking for? Gravitational? Nuclear? Chemical?
I think gravitational. I need to know if a bomb would explode an asteroid or not, and I was going to do a comparison on the energy of the bomb (which I've already figured out), to the binding energy of the asteroid.
 
Note that the binding energy of an asteroid also contributes to its mass via E=mc2 as every energy in the rest frame does, but the contribution is completely negligible.
 
  • Like
Likes   Reactions: Tris Fray Potter
... if the idea is to destroy the asteroid before it arrives at some target, detonating it won't remove it's kinetic energy (though distributing the bits over a big volume can reduce the amount of mass that strikes the target. Phil Plait has an artical about it.
 
  • Like
Likes   Reactions: Tris Fray Potter