- #1

Redwaves

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- Homework Statement
- The binding energy per nucleon of the ##^3 He## nucleus is 2.6 MeV. Deduce the binding energy per nucleon of tritium from the following information: (1) The mass energies of isolated protons, neutrons and electrons are 938.3 MeV, 939,6 MeV and 0.5 MeV. (2) Tritium decays by the reaction ##^3 H ---> ^3 He + e + v##, where kinetic energy of the final particles is 0.0186 MeV. (3) the mass energy of the antineutrino v is negligible on the MeV scale.

- Relevant Equations
- ##E_i = E_f##

##E^2 = \vec{P}^2 c^2 + m^2 c^4##

##E = \gamma mc^2##

Hi,

I know from conservation of energy that ##E_i = E_f##

Thus, ## M_h c^2 + binding energy = M_{he}c^2+ M_e c^2 + K = M_{he}c^2 + 0.5 MeV + 0.0186 MeV##

If I'm right I have to find ##M_{he}c^2##, but something is missing in my understanding, since I don't see how to find that mass energy ##M_{he}c^2##.

Is the binding energy the difference between initial energy and final energy?

Is the mass energy of an atom the sum of all the neutrons, proton and electrons and the binding energy?

I know from conservation of energy that ##E_i = E_f##

Thus, ## M_h c^2 + binding energy = M_{he}c^2+ M_e c^2 + K = M_{he}c^2 + 0.5 MeV + 0.0186 MeV##

If I'm right I have to find ##M_{he}c^2##, but something is missing in my understanding, since I don't see how to find that mass energy ##M_{he}c^2##.

Is the binding energy the difference between initial energy and final energy?

Is the mass energy of an atom the sum of all the neutrons, proton and electrons and the binding energy?