the earth has a n angular speed of 7.272 x 10 ^ -5 rad/s in it;s rotation. Find the new angular speed if an asteroid ( m = 1.17 x 10 ^ 22kg) hits the earth while traveling at 1.41 x10^3 m/s.
the asteroid hits the earth dead center
The Attempt at a Solution
(La)f + ( Le) f = ( La) + (Le)i
Wf( MaR + 2/5MeR^2) = maRV + 2.5MeR^2W
Wf = ( MaVa + 2/5MeRWe) / ( Ma + 2/5MeR)
this is what I have as final angular speed but it gives me an answer faster than the earths initial angular momentum when the books answer is slightly less than the earths initial answer.