[Astrophysics] Star luminosity-radius-temperature problem

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SUMMARY

The discussion centers on the calculation of the luminosity-radius-temperature relationship for a Cepheid variable star, specifically addressing a homework problem involving light variation of 2 magnitudes. The key formulas used include the logarithmic relationship between luminosity and radius, as well as the effective temperatures at maximum (6000K) and minimum (5000K) luminosity. The participant initially struggled with the application of logarithmic calculations but ultimately resolved the issue by recognizing the inverse nature of the magnitude scale, confirming that both methods yield consistent results.

PREREQUISITES
  • Understanding of Cepheid variable stars and their light variation.
  • Familiarity with the concepts of luminosity and effective temperature.
  • Knowledge of logarithmic functions and their application in astrophysics.
  • Proficiency in using the Stefan-Boltzmann law for stellar calculations.
NEXT STEPS
  • Study the application of the Stefan-Boltzmann law in stellar astrophysics.
  • Learn about the inverse magnitude scale and its implications in photometry.
  • Explore the relationship between luminosity, radius, and temperature in more complex stellar models.
  • Investigate the properties and significance of Cepheid variables in distance measurement in astronomy.
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Astronomy students, astrophysicists, and anyone interested in the calculations related to stellar properties and the behavior of Cepheid variable stars.

Andrev
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Hi!

Homework Statement



The light variation of a Cepheid is 2 mag,if its effective temperature at maximum luminosity is
6000K, while at minimum is 5000K, please estimate the ratio of its maximum and minimum
radius.

Homework Equations



$$\Delta m=-2,5lg\frac{L_{min}}{L_{max}}$$
$$lg\frac{L_{min}}{L_{max}}=2lg\frac{R_{min}}{R_{max}}+4lg\frac{L_{min}}{L_{max}}$$

The Attempt at a Solution



Well, actually I should solve the problem with those two formulas above. My question is: why I can not just calculate the $$\frac{L_{min}}{L_{max}}$$ and solve the $$\frac{L_{min}}{L_{max}}=\frac{4\pi R_{min}^2 \cdot T_{min}^4\cdot \sigma}{4\pi R_{max}^2 \cdot T_{max}^4\cdot \sigma}$$ equation? Why I have to calculate with the lgs? As I studied the problem it looked for me that these two methods are equal but I got different results.

Thanks in advance,


Andrev
 
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Sorry for spamming the forum with this I solved it on my own:

Of course I can calculate with the form without lgs too. I missed the calculation at the beginning: I forgot that the magnitude scale is inverse, so $$-0.4\cdot (m_1-m_2)=-0.4 \cdot \Delta m <0$$ It is ok now. Andrev
 
Last edited:

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