At what angle will a box start to slide

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SUMMARY

The discussion focuses on calculating the angle at which two boxes of nails (20 kg and 10 kg) begin to slide down a tilted plank, given a coefficient of static friction of 0.4. The static friction force is calculated using the equation |Fs| = µs|mg|, resulting in 78.4 N for the 20 kg box and 39.2 N for the 10 kg box. The normal force changes when the plank is tilted, necessitating adjustments in calculations. The scenario is compared to a ramp situation, emphasizing the importance of understanding forces acting on the boxes.

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Homework Statement



So there 2 boxes of nails being lifted at a construction site and one box is 20 kg and the other 10 kg. and the plank tilts towards the heavier box. if the coeficient of static friction is 0.4 draw a FBD for each box of nails and use it to calculate the angle at which each box begins to slide.

Homework Equations





The Attempt at a Solution



|Fs| = µs|mg|

20 Kg box is 78.4 N
10 kg Box is 39.2 N

And now I am not sure how to continue...
 
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TheronSimon said:

Homework Statement



So there 2 boxes of nails being lifted at a construction site and one box is 20 kg and the other 10 kg. and the plank tilts towards the heavier box. if the coeficient of static friction is 0.4 draw a FBD for each box of nails and use it to calculate the angle at which each box begins to slide.

Homework Equations





The Attempt at a Solution



|Fs| = µs|mg|

20 Kg box is 78.4 N
10 kg Box is 39.2 N

And now I am not sure how to continue...


When the board is at an angle, the normal reaction force will no longer equal mg in size, so you need to account for that.

Question: is this situation really any different to having the boxes of nails on a ramp? It certainly would be if the crane lifting them was causing them to accelerate up or down, but if they are traveling at steady speed?
 

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