At what point is Electric Potential zero

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SUMMARY

The electric potential is zero at a point located 0.8 cm away from the -2μC charge when two charges of 3μC and -2μC are placed 2 cm apart. The equation used for the calculation is based on the superposition principle of electric potential, represented as Φ=kq/r^2. The solution involves setting the potentials equal to each other and solving for the distance from the positive charge, confirming that the point lies outside the segment connecting the two charges.

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  • Understanding of electric potential and superposition principle
  • Familiarity with Coulomb's law and the formula Φ=kq/r^2
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1. The problem statement
Two charges of 3μC and -2μC are placed 2cm apart. At what point along their connecting line is electric potential zero?

Homework Equations


Electric potential superposition Φ=Φ1-Φ2 since q2 is negative
Φ=kq/r^2

The Attempt at a Solution


Let’s say the charges are on the x axis. Their coordinates would be x1 and x1+2
The coordinate of the point we’re looking for is x
so kq1/(x-x1) - kq2/(x-x1-2) = 0
3/(x-x1) = 2/(x-x1-2)
x-x1=6
So the point is 6cm away from q1, but the answer says 0.8cm away from q2 and I don’t get it
 
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Make yourself a drawing. Call x the distance from the 3 μC charge to point P you are looking for. What is the distance from the -2 μC to point P? Is point P in between the two charges, to the left of the distribution or to the right of the distribution? Also, please use parentheses in your algebraic expressions to group together quantities that belong together.
 
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kuruman said:
Make yourself a drawing. Call x the distance from the 3 μC charge to point P you are looking for. What is the distance from the -2 μC to point P? Is point P in between the two charges, to the left of the distribution or to the right of the distribution? Also, please use parentheses in your algebraic expressions to group together quantities that belong together.

Got the answer. Thank you.
 

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