- #1

Sekonda

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Here's the question

Now I wanted to check if my thought process was correct and thus my formulation. Some sodium atom is initially excited, emits EM wave with stated λ and then de-excites to the ground state.

However, this is Sodium so I think we approximate the energy levels using the equation:

[tex]E=-Z^{2}\frac{13.61eV}{(n-\delta_{i})^{2}}[/tex]

Such that we have

[tex]E_{initial}-E_{ground}=E_{wave}[/tex]

which is

[tex]E_{initial}=\frac{hc}{\lambda}-Z^{2}\frac{13.61}{(3-1.35)^{2}}[/tex]

For Z=11 and since we write the ground state of sodium as 1s{2}2s{2}2p{6}3s{1} I used n=3 and δi=δs. I got the initial state energy as -600eV though have no idea if I've done this correct.