karush
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| (c) $\displaystyle\frac{n(B\cup A')}{n(U)}=\frac{35}{100}=\frac{7}{20}$ |
karush said:so I have $B\cup A'$
(c)
$\displaystyle\frac{n(B\cup A')}{n(U)}=\frac{35}{100}=\frac{7}{20}$