Available energy in β+ and β- nuclear reaction

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Homework Help Overview

The discussion revolves around calculating the available energy in β+ and β- nuclear reactions, specifically focusing on the differences in mass considerations when using atomic versus nucleon masses in the energy equations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the formulas for available energy, questioning the treatment of electron mass in the context of β+ and β- reactions. There is uncertainty about why the mass of electrons is included in one case but not the other.

Discussion Status

Some participants are seeking clarification on the definitions and implications of the available energy in these reactions. There is an ongoing exploration of the underlying assumptions regarding mass and energy calculations, with no clear consensus reached yet.

Contextual Notes

Participants mention the challenge of translating terminology and concepts from French, which may affect their understanding. There is also a note about the professor's preference for using positive values for available energy, which may influence the discussion.

duchuy
Messages
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Homework Statement
Formula demonstration
Relevant Equations
Ed = [Mn(X) – (Mn(Y) + m(e))] c2
Hi,
I understood that to calculate the available energy in these two reactions could be calculated from Ed = [Mn(X) – (Mn(Y) + m(e))] c^2, but when I have to change use the atoms' mass instead of the nucleons' mass, it gives out two different formulas :
Ed = [M(X) – M (Y)] c2 for β-
Ed = [M(X) – (M(Y) + 2 m(e))].c2 for Ed = [M(X) – (M(Y) + 2 m(e))].c2 for β+
Can someone please explain to me why for β-, the mass of the electron isn't taken into consideration whilst for β+, we'd have to add the mass of two electrons ( when we are using the mass of the atom to calculate ).
Sorry if I have misused any vocabulary, I translated this from french.
Thank you so much for your help!
 
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kuruman said:
Please be more specific. What does Ed represent? What two reactions is Ed associated with?
I'm so sorry for that.
Ed represents the available energy. The formula Ed = [Mn(X) – (Mn(Y) + m(e))] c2 uses the mass of the entire atom and is used for β+ and - reaction.
But when only the mass of the nuclei are given, we end up with two different formulas :
Ed = [M(X) – M (Y)] c2 for β-
Ed = [M(X) – (M(Y) + 2 m(e))].c2 for Ed = [M(X) – (M(Y) + 2 m(e))].c2 for β+
I just don't understand what happened to the mass of the electrons in these two reactions.
Thank you!
 
duchuy said:
Ed represents the available energy.
The available energy when what happens?
 
kuruman said:
The available energy when what happens?
I think it's the available energy in an atom with either an excess of neutron or proton depending on the β radioactivity. I'm not quite sure though sorry, it's just what's written in the text that we have to learn...
 
I think that the prof doesn't like negative signs, so instead of using the energy released which is going to have a negative value when we consider the system, he just uses the available energy so the energy would be positive. I didn't get the chance to ask him since all classes are uploaded videos...
 

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