Average acceleration and average force

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SUMMARY

The discussion centers on calculating the average acceleration and average force exerted on a steel ball with a mass of 17 grams, launched at a speed of 6 m/s, which comes to a stop over a distance of 1 mm. The average acceleration calculated using the formula Vf² - Vi² = 2a*d yields a value of -1800 m/s², indicating a significant deceleration. The force exerted on the ball, and consequently on the eyeball, is substantial due to the rapid deceleration over a minimal distance, emphasizing the physics of high-speed impacts.

PREREQUISITES
  • Understanding of kinematic equations, specifically Vf² - Vi² = 2a*d
  • Basic knowledge of Newton's second law of motion
  • Familiarity with unit conversions, particularly grams to kilograms
  • Concept of force and acceleration in physics
NEXT STEPS
  • Review Newton's second law of motion and its applications
  • Explore kinematic equations in-depth for various motion scenarios
  • Learn about impulse and momentum to understand force applications better
  • Investigate real-world examples of high-speed impacts and their consequences
USEFUL FOR

Physics students, educators, and anyone interested in the dynamics of motion and force, particularly in high-speed scenarios.

tooperoo
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Homework Statement


Steel ball with a mass 17 grams, is launched at a speed of 6 m/s, into someones eye. The ball comes to a rest over a distance of 1mm.

A) What is the average acceleration experienced by the ball to stop it?

B) What is the deaccelerating force that must be exerted on the ball (by the eyeball), and thus, what is the average force on the eyeball?


Homework Equations





The Attempt at a Solution



I tried using the Vf^2 - Vi^2 = 2a*d (where d is displacement, vf is final veloctiy, vi is initial velocity and a is acceleration) but came out with -18m/s^2 for the acceleration. I don't think that is right however



Any help is greatly appreciated
 
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Check your arithmetic.
 
I stuffed up the arithmetic.
Answer should be -1800. Is that right? Seems big for acceleration.
 
Check the numbers, I get an even bigger acceleration. Anyway yes, it is big for an acceleration, but also from 6 m/s (21.6 Km/h) to rest in only 1 mm is really a lot... to stop something that fast in such short distance will require (of course depending on mass) a huge force, at least for usual objects (therefore not too light).
 
tooperoo said:
I stuffed up the arithmetic.
Answer should be -1800. Is that right? Seems big for acceleration.
You're still off by a factor of 10, so recheck that math. Yes, it's big. But 1 mm is a small distance to come to rest in.
 

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