Average Acceleration During a Collision

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SUMMARY

The average acceleration of a tennis ball during a collision with a wall can be calculated using the formula α = (ωf - ωi) / Δt. In this scenario, the initial velocity (ωi) is 7.97 m/s to the right, and the final velocity (ωf) is -5.07 m/s to the left, with a contact time (Δt) of 0.011 seconds. Substituting these values into the equation yields an average acceleration of approximately -1,000 m/s², indicating a rapid change in velocity upon impact with the wall.

PREREQUISITES
  • Understanding of basic kinematics
  • Familiarity with the concepts of velocity and acceleration
  • Knowledge of the formula for average acceleration
  • Ability to perform unit conversions and calculations
NEXT STEPS
  • Review the principles of momentum and impulse in collisions
  • Learn about the effects of different materials on collision outcomes
  • Explore the concept of elastic vs. inelastic collisions
  • Investigate how to calculate average acceleration in various scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators seeking to enhance their understanding of collision dynamics.

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Homework Statement


A tennis ball with a velocity of 7.97 m/s to the right is thrown perpendicularly at a wall. After striking the wall, the ball rebounds in the opposite direction with a velocity of −5.07 m/s to the left. If the ball is in contact with the wall for 0.011 s, what is the average acceleration of the ball while it is in contact with the wall? Answer in units of m/s^2.


Homework Equations


The one that I assumed was the right equation was
ωf=ωi+αΔt
(ωf=final velocity) (ωi=initial velocity) (α=acceleration) (Δt =change in time)


The Attempt at a Solution


I just plugged the numbers into the formula and solved for α, but the answer was wrong. What I am I doing incorrectly?
 
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