Average electric field over a spherical surface

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 6K views
JD_PM
Messages
1,125
Reaction score
156

Homework Statement


I was working out problem 4, chapter 3 of Introduction to Electrodynamics by Griffiths:

a) Show that the average electric field over a spherical surface, due to charges outside the sphere, is the same as the field at the centre.

b) What is the average due to charges inside the sphere?

The Attempt at a Solution



I know the solution, but there are a few aspects I do not see:

Screenshot (93).png

Screenshot (94).png

Here you have the image Griffiths makes reference at:

Screenshot (95).png


Why ##z^2 + r^2 - R^2 = z - Rcos \theta## (law of cosines developement)?
 

Attachments

  • Screenshot (92).png
    Screenshot (92).png
    16 KB · Views: 692
  • Screenshot (93).png
    Screenshot (93).png
    15.3 KB · Views: 1,933
  • Screenshot (94).png
    Screenshot (94).png
    33.6 KB · Views: 1,873
  • Screenshot (95).png
    Screenshot (95).png
    7.2 KB · Views: 1,854
Physics news on Phys.org
JD_PM said:
Why ##z^2 + r^2 - R^2 = z - Rcos \theta## (law of cosines developement)?
This equality is not correct. Instead, note the following substitution
upload_2019-2-19_13-44-35.png
 

Attachments

  • upload_2019-2-19_13-44-35.png
    upload_2019-2-19_13-44-35.png
    4.2 KB · Views: 1,655
  • Like
Likes   Reactions: JD_PM